ourbluenation
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Thu Feb-02-06 09:39 PM
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kid needs math help - I'm clueless |
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5x to the 4th power minus 80????
wtf?
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miss_american_pie
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Thu Feb-02-06 09:41 PM
Response to Original message |
ourbluenation
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Thu Feb-02-06 09:42 PM
Response to Reply #1 |
3. the 12 year old say nix on your answer. thx though. |
miss_american_pie
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Thu Feb-02-06 09:44 PM
Response to Reply #3 |
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maybe I should have done my algebra homework myself
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Rabrrrrrr
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Thu Feb-02-06 09:42 PM
Response to Original message |
2. That's a nice statement. |
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But what is the math problem? Is there an actual equation?
is he supposed to solve for x?
If so, just find the number that when raised to the fourth power and then multiplied by 5 equals 80, assuming that the equation is 5x^4-80=0. which of course we don't know, because you didn't acually give us a full problem.
That's a trivially easy question, if so.
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ourbluenation
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Thu Feb-02-06 09:43 PM
Response to Reply #2 |
5. omg this is so not my thing - she says it;s a polynomial |
Rabrrrrrr
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Thu Feb-02-06 09:44 PM
Response to Reply #5 |
7. Well, yes, it's a polynomial - but is there an actual question? |
LisaL
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Thu Feb-02-06 09:45 PM
Response to Reply #5 |
9. Just copy the freaking problem exactly as it is written. |
JVS
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Thu Feb-02-06 09:43 PM
Response to Original message |
4. What is it asking to do? |
ourbluenation
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Thu Feb-02-06 09:44 PM
Response to Reply #4 |
LisaL
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Thu Feb-02-06 09:45 PM
Response to Reply #8 |
10. Post it as it is written. |
Whoa_Nelly
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Thu Feb-02-06 09:47 PM
Response to Reply #10 |
11. or scan it and post it from photobucket, or...? |
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Edited on Thu Feb-02-06 09:48 PM by Whoa_Nelly
Because, as Rabrrrrrr said: it's easy if the problem is as he guessed it might be written.
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ourbluenation
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Thu Feb-02-06 09:48 PM
Response to Reply #10 |
12. she's getting her book - hang on.... |
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ok
5x 4 - 80
the 4 is to the 4th power
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Rabrrrrrr
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Thu Feb-02-06 09:52 PM
Response to Reply #12 |
19. Christ almighty, that still isn't a problem or question. |
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It's a statement.
As a number of others have said, post the actual question, and post it EXACTLY as it written. Mathematics doesn't deal in "feelings" or "close enoughs" - just write the question.
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JVS
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Thu Feb-02-06 09:48 PM
Response to Reply #8 |
13. 5*(x-2)*(x+2)*(x^2+4) |
JVS
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Thu Feb-02-06 09:49 PM
Response to Reply #13 |
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Edited on Thu Feb-02-06 09:50 PM by JVS
:party:
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Whoa_Nelly
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Thu Feb-02-06 09:50 PM
Response to Reply #13 |
17. I don't think it's a factoring of 4 |
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but is actually x^4 power...as Rabrrrrr originally guessed
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aclog
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Thu Feb-02-06 09:48 PM
Response to Reply #8 |
14. I did it on paper so somebody back me up but I think its |
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5*(x-2)*(x+2)*(x^2+4)
you can technically factor x^2+4 but I'm guessing that counts as reduced for your purpose
if no one else double checks me I'll factor it on the computer to be sure its right
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ourbluenation
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Thu Feb-02-06 09:51 PM
Response to Reply #14 |
18. she says, and I quote, "yes - that's it - let me call Jenny!" |
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She and Miss Jenny are going over it now on the phone....
Now she says, "Jeez - these people are smart!"
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Rabrrrrrr
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Thu Feb-02-06 09:50 PM
Response to Reply #8 |
16. Ah, now we have an actual problem - the first step in math, |
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especially in asking for help in math, is to give the actual question.
5x^4-80 when factored becomes (5x^2+20)(x^2-4)
which is: 5(x-2)(x+2)(x^2+4)
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aclog
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Thu Feb-02-06 09:53 PM
Response to Reply #16 |
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5x^4-80 =5*(x^4-16) =5*<(x^2)^2-4^2> =5*<(x^2-4)*(x^2+4)> =5*<(x-2)*(x+2)*(x^2+4)>
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Rabrrrrrr
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Thu Feb-02-06 09:55 PM
Response to Reply #21 |
23. Um....yeah. Thanks for explaining that to me. |
aclog
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Thu Feb-02-06 09:57 PM
Response to Reply #23 |
24. I replied to the wrong post |
ourbluenation
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Thu Feb-02-06 09:53 PM
Response to Original message |
20. Hi - This is Olivia...thanks a lot - algebra 1 is really hard... |
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sometimes.
PS) Bush wouldn't have gotten that even with some extra thinkerating!
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Rabrrrrrr
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Thu Feb-02-06 09:54 PM
Response to Reply #20 |
22. You are welcome, but let me re-iterate, that if you are going |
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to ask for help, you need to actually post the question.
If you (or your mom) had done that to begin with, you would have had your answer in five or so less minutes.
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