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September American death rates in Al Anbar Province are 13 times higher than the rest of Iraq

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Quixote1818 Donating Member (1000+ posts) Send PM | Profile | Ignore Wed Sep-19-07 08:42 PM
Original message
September American death rates in Al Anbar Province are 13 times higher than the rest of Iraq
Edited on Wed Sep-19-07 08:44 PM by Quixote1818
So far 8 out of 49 of the deaths occurred in Al Anbar Province which has a population of 400,000 in a country with over 27 Million people.

Al Anbar Province has only about 1.5 % of Iraq's population yet 16% of American deaths have occurred there. That means (if my math is correct) American death rates in Al Anbar Province are 13 times higher than they are in the rest of Iraq based on percent of population.

I thought Al Anbar Province was supposed to be where things were going the best for us? If you look at the numbers is seems Bush is using fuzzy math with Al Anbar Province's success. An American's probability of dying in Al Anbar is 13 times higher than in the rest of the country.



Link: http://icasualties.org/oif/prdDetails.aspx?hndRef=9-2007



Question: Is Albu Hyatt - Anbar, considered Al Anbar Province? 4 of the 8 deaths I referred to occurred there.
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frogcycle Donating Member (1000+ posts) Send PM | Profile | Ignore Wed Sep-19-07 09:17 PM
Response to Original message
1. Very fuzzy
An American's probability of dying in Al Anbar has nothing to do with the number of Iraqis there vs elsewhere. Your "American deaths per Iraqi" is meaningless. Anbar has vast tracts of empty desert. In the populous areas the "death per Iraqi" is probably still higher than Baghdad, but not 13 times. Do your math based on the number of deaths per American troop in the local area, like around Al Asad. Fatalities in Anbar in August were also 16% of total, by the way. In Jan it was about 14%
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