could read this or not.
http://www.spinbitz.net/anpheon.org/anpheonNews.htmlIn Bad Astronomy and Universe Today forums, the following calculation was presented (please see the link for accurate rendering of equations).
http://www.bautforum.com/showthread.php?t=41877The author says, "Well, let’s see what mainstream physics has to say about it." Well, mainstream physics tends to inject it's own biases and preconceptions, equations and assumptions into an entirely different model where they simply don't apply. This is a classic case of "paradigm incommensurability," as we will see. Aspects of one paradigm generally don't apply to the other, and vice versa.
See my post-comments below for the quick and easy check and mate.
Okay, this has already been written once in several mails, now it is collected in one concise message. Is the sun a ball of hot gas with fusion in the centre or is it a discharge according to Juergens? Well, let’s see what mainstream physics has to say about it.
Total Energy produced by the Sun in 1 second:
From the general mainstream model the fusion in the core of the sun produces 4.3 million tonnes (4.3 10^9 kg) equivalent of energy per second so with the well known equation E = MC2 (Thanks Albert !, E is energy, M is the totall mass and C is the velocity of light 3 10^8 m/s) we can find the total power P:
P = 4.3 10^9 x (3 10^8)2 / 1 second = 3.9 10^26 Joules/s
With an arbitrary voltage of a billion volts from the Sun and exterior space, according to Juergens in a “double layer” above the suns surface and P = UI (where U is the total potential drop in Volts and I is the total current in Amperes), we can calculate a current
I = P / U = 3.9 10^26 / 109 = 3.9 10^17 A.
So, now we come to the circuit around the sun, inflowing current in the equatorial plane and outflowing current along the poles of the sun, this all in accordance with Alfvén’s circuit model (see Cosmic Plasma, page 55, Figure III.7).
Learning from the Earth where the current sheet thickness is on the order of the Earth’s radius, therefore we will assume that the current flowing to the sun has a thickness on the order of the suns radius.
Now we look at what may be observed near Earth if indeed this current flows in the circuit, driving the energy output of the sun as in Juergens’ model.
For a plane current sheet we can estimate the magnetic field by using Maxwell's equations. One equation, Ampere's Law, says that the variation of the magnetic field produced by a current is given by:
curl B = mu0 (J + epsilon0 dE/dt),
here curl is an operator that basically takes the derivative of the magnetic field in all three cartesian coordinates. In the case when we have a sheet of current, we can simplify this equation. We assume time stationarity (the sun shines at basically the same rate without major variations so that is no real problem) which means that any time derivative, like dE/dt will be 0. Assuming an infinite sheet in the x and y direction there is only variation in z and the equation simplifies to:
dB/dz = mu0 J,
and here we can make an estimate of the variation of the magnetic field from one side of the current sheet to the other by changing this differential into a difference dB/dz -> delta B / delta z. The delta B we do not know but the delta z is the thickness of the current sheet, so we find:
Delta B / L = mu0 J,
where we know L, the radius of the sun (7 10^8 m), and we can calculate J from the total current I (above) and saying that it flows through a “ribbon” of L wide and a circumference of 2 pi REarth-sun (1 AU = 1.5 10^11 m),
J = 3.9 10^17 / (2 pi 1.5 10^11 7 10^8 = 6 10-4 Amp/m2
and thus with mu0 = 4 pi 10-7 we find for the magnetic field near the Earth produced by that current system:
delta B = mu0 J L = 0.5 Tesla
Now, what magnetic field strengt his measured near the Earth? We measure field in the nano-Tesla range (see e.g. data from the Cluster spacecraft in the solar wind (the middle part in the linked plot), so that means that this model is roughly 1 billion (American) 109 times too strong, give or take a factor of 3!
And then other observations, e.g. by the Ulysses spacecraft over the poles of the sun (here is a plot of the magnetic field strength measured by the mission from start to date), have not shown any signature AFAIK of strong toroidal magnetic fields associated with the outflowing currents.
Impressive calculations perhaps, but the end result is entirely useless because of a very simple error right at the beginning. The calculation bases its power output (3.9 10^26 Joules) on the "fusion in the core" from the "general mainstream model." From that result, right out of mainstream physics, it then derives the current supposedly expected from the EU model. But in the EU model there is no fusion going on in the core. The only fusion going on is that at the photosphere. The gravitational fusion-in-the-core assumption is a purely hypothetical aspect of the mainstream model only. indeed, gravitational thermonuclear fusion has never been achieved in the laboratory, while the z-pinch fusion in the EU model has been achieved over and over. This calculation, therefore, uses a VASTLY inflated number for the total power output and hence for its derived magnetic field strength at the distance of the earth.
It is therefore fundamentally incorrect due to faulty assumptions right at the beginning. A case of injecting the assumptions of the favored model into the opponent to render it incoherent. A subtle straw-man effigy derived from an unconscious paradigm incommensurability.
Printer-friendly format
Email this thread to a friend
Bookmark this thread
(1000+ posts)
Send PM |
Profile |
Ignore
