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[quaker bill]

58. How many kilos would that be?

If I recall correctly, a critical mass is about 2.2 Kg. Most of mass and volume of the nukes used in WWII was conventional explosive used to bring the mass together and compress it. I don't think they did, but let's say they went generous and used 3 Kg. They would not have wanted to go too generous because as you exceed critical mass in a bomb, the shielding to keep it from going critical on its own would become a technical problem.

So while I think the estimate is wildly inaccurate, let's posit for a moment that there is 22,000 Kg there. Now the odds are pretty huge that if there were that quantity of plutonium in a reactor, the accident would have quickly removed a very big chunk of Japan. But let's keep going with it for a moment. A cubic foot of water weighs about 30Kg so a cubic mile of water weighs roughly 4,415,938,560,000 Kg. So now we suspend disbelief for just another moment and dissolve the entire 22,000 Kg in one cubic mile of water. You would get a plutonium solution 0.000005 grams per Kg (liter) of water. This is roughly 5 parts per billion, not something you would want to drink for sure, but the salt would kill you first and many times over.

There are in fact 100s of millions of cubic miles of water in the Pacific. This is the problem with mass difference. Evenly divided, even 10,000 Hiroshima bombs dilutes out to near homeopathic orders of magnitude. There would only be a thousand or two plutonium atoms per cubic mile of water, odds are strong at this dilution that most random 1 liter samples would not have even one plutonium atom in it.

The math just does not work. There simply is not enough mass to cause the problems you posit.